Solve sqrt{160/6}=

$$\sqrt { \frac { 160 } { 6 } } =$$

Evaluate

$$\frac{4\sqrt{15}}{3}\approx 5.163977795$$

Solution Steps

Reduce the fraction \frac{160}{6} to lowest terms by extracting and canceling out 2.

$$\sqrt{\frac{80}{3}}$$

Rewrite the square root of the division \sqrt{\frac{80}{3}} as the division of square roots \frac{\sqrt{80}}{\sqrt{3}}.

$$\frac{\sqrt{80}}{\sqrt{3}}$$

Factor 80=4^{2}\times 5. Rewrite the square root of the product \sqrt{4^{2}\times 5} as the product of square roots \sqrt{4^{2}}\sqrt{5}. Take the square root of 4^{2}.

$$\frac{4\sqrt{5}}{\sqrt{3}}$$

Rationalize the denominator of \frac{4\sqrt{5}}{\sqrt{3}} by multiplying numerator and denominator by \sqrt{3}.

$$\frac{4\sqrt{5}\sqrt{3}}{\left(\sqrt{3}\right)^{2}}$$

The square of \sqrt{3} is 3.

$$\frac{4\sqrt{5}\sqrt{3}}{3}$$

To multiply \sqrt{5} and \sqrt{3}, multiply the numbers under the square root.

$$\frac{4\sqrt{15}}{3}$$