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\left(\sqrt{\frac{\frac{\frac{7}{6}}{2-\frac{1}{4}}-\left(\frac{1}{3}-\frac{1}{4}\right)}{\frac{3}{7}-\frac{2}{21}}}\right)^{0,01}
Subtract \frac{1}{3} from \frac{3}{2} to get \frac{7}{6}.
\left(\sqrt{\frac{\frac{\frac{7}{6}}{\frac{7}{4}}-\left(\frac{1}{3}-\frac{1}{4}\right)}{\frac{3}{7}-\frac{2}{21}}}\right)^{0,01}
Subtract \frac{1}{4} from 2 to get \frac{7}{4}.
\left(\sqrt{\frac{\frac{7}{6}\times \frac{4}{7}-\left(\frac{1}{3}-\frac{1}{4}\right)}{\frac{3}{7}-\frac{2}{21}}}\right)^{0,01}
Divide \frac{7}{6} by \frac{7}{4} by multiplying \frac{7}{6} by the reciprocal of \frac{7}{4}.
\left(\sqrt{\frac{\frac{2}{3}-\left(\frac{1}{3}-\frac{1}{4}\right)}{\frac{3}{7}-\frac{2}{21}}}\right)^{0,01}
Multiply \frac{7}{6} and \frac{4}{7} to get \frac{2}{3}.
\left(\sqrt{\frac{\frac{2}{3}-\frac{1}{12}}{\frac{3}{7}-\frac{2}{21}}}\right)^{0,01}
Subtract \frac{1}{4} from \frac{1}{3} to get \frac{1}{12}.
\left(\sqrt{\frac{\frac{7}{12}}{\frac{3}{7}-\frac{2}{21}}}\right)^{0,01}
Subtract \frac{1}{12} from \frac{2}{3} to get \frac{7}{12}.
\left(\sqrt{\frac{\frac{7}{12}}{\frac{1}{3}}}\right)^{0,01}
Subtract \frac{2}{21} from \frac{3}{7} to get \frac{1}{3}.
\left(\sqrt{\frac{7}{12}\times 3}\right)^{0,01}
Divide \frac{7}{12} by \frac{1}{3} by multiplying \frac{7}{12} by the reciprocal of \frac{1}{3}.
\left(\sqrt{\frac{7}{4}}\right)^{0,01}
Multiply \frac{7}{12} and 3 to get \frac{7}{4}.