Solve sinx^2+(2a+2)x+a=0

$$\sin x ^ { 2 } + ( 2 a + 2 ) x + a = 0$$

Solve for a

$$a=-\frac{\sin(x^{2})+2x}{2x+1}$$

$$x\neq -\frac{1}{2}$$

Steps for Solving Linear Equation

Use the distributive property to multiply 2a+2 by x.

$$\sin(x^{2})+2ax+2x+a=0$$

Subtract \sin(x^{2}) from both sides. Anything subtracted from zero gives its negation.

$$2ax+2x+a=-\sin(x^{2})$$

Subtract 2x from both sides.

$$2ax+a=-\sin(x^{2})-2x$$

Combine all terms containing a.

$$\left(2x+1\right)a=-\sin(x^{2})-2x$$

Divide both sides by 2x+1.

$$\frac{\left(2x+1\right)a}{2x+1}=\frac{-\sin(x^{2})-2x}{2x+1}$$

Dividing by 2x+1 undoes the multiplication by 2x+1.

$$a=\frac{-\sin(x^{2})-2x}{2x+1}$$

Divide -\sin(x^{2})-2x by 2x+1.

$$a=-\frac{\sin(x^{2})+2x}{2x+1}$$