Evaluate
-\frac{\sqrt{3}}{2}\approx -0.866025404
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\sin(180+60)=\sin(180)\cos(60)+\sin(60)\cos(180)
Use \sin(x+y)=\sin(x)\cos(y)+\sin(y)\cos(x) where x=180 and y=60 to obtain the result.
0\cos(60)+\sin(60)\cos(180)
Get the value of \sin(180) from trigonometric values table.
0\times \frac{1}{2}+\sin(60)\cos(180)
Get the value of \cos(60) from trigonometric values table.
0\times \frac{1}{2}+\frac{\sqrt{3}}{2}\cos(180)
Get the value of \sin(60) from trigonometric values table.
0\times \frac{1}{2}+\frac{\sqrt{3}}{2}\left(-1\right)
Get the value of \cos(180) from trigonometric values table.
-\frac{\sqrt{3}}{2}
Do the calculations.
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