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\sin(180+45)=\sin(180)\cos(45)+\sin(45)\cos(180)
Use \sin(x+y)=\sin(x)\cos(y)+\sin(y)\cos(x) where x=180 and y=45 to obtain the result.
0\cos(45)+\sin(45)\cos(180)
Get the value of \sin(180) from trigonometric values table.
0\times \frac{\sqrt{2}}{2}+\sin(45)\cos(180)
Get the value of \cos(45) from trigonometric values table.
0\times \frac{\sqrt{2}}{2}+\frac{\sqrt{2}}{2}\cos(180)
Get the value of \sin(45) from trigonometric values table.
0\times \frac{\sqrt{2}}{2}+\frac{\sqrt{2}}{2}\left(-1\right)
Get the value of \cos(180) from trigonometric values table.
-\frac{\sqrt{2}}{2}
Do the calculations.