Solve sin(z)=xc

$$\sin ( z ) = xc$$

Solve for c

$$\left\{\begin{matrix}c=\frac{\sin(z)}{x}\text{, }&x\neq 0\\c\in \mathrm{R}\text{, }&\exists n_{1}\in \mathrm{Z}\text{ : }z=\pi n_{1}\text{ and }x=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$xc=\sin(z)$$

Divide both sides by x.

$$\frac{xc}{x}=\frac{\sin(z)}{x}$$

Dividing by x undoes the multiplication by x.

$$c=\frac{\sin(z)}{x}$$

Solve for x

$$\left\{\begin{matrix}x=\frac{\sin(z)}{c}\text{, }&c\neq 0\\x\in \mathrm{R}\text{, }&\exists n_{1}\in \mathrm{Z}\text{ : }z=\pi n_{1}\text{ and }c=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$xc=\sin(z)$$

The equation is in standard form.

$$cx=\sin(z)$$

Divide both sides by c.

$$\frac{cx}{c}=\frac{\sin(z)}{c}$$

Dividing by c undoes the multiplication by c.

$$x=\frac{\sin(z)}{c}$$