Solve for T
T=25\cos(\theta )
\nexists n_{1}\in \mathrm{Z}\text{ : }\theta =\pi n_{1}+\frac{\pi }{2}
Solve for θ
\theta =-\arccos(\frac{T}{25})+2\pi n_{1}\text{, }n_{1}\in \mathrm{Z}
\theta =\arccos(\frac{T}{25})+2\pi n_{2}\text{, }n_{2}\in \mathrm{Z}\text{, }T\leq 25\text{ and }T\geq -25\text{ and }T\neq 0
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T\sec(\theta )=25
Variable T cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by T.
\sec(\theta )T=25
The equation is in standard form.
\frac{\sec(\theta )T}{\sec(\theta )}=\frac{25}{\sec(\theta )}
Divide both sides by \sec(\theta ).
T=\frac{25}{\sec(\theta )}
Dividing by \sec(\theta ) undoes the multiplication by \sec(\theta ).
T=25\cos(\theta )
Divide 25 by \sec(\theta ).
T=25\cos(\theta )\text{, }T\neq 0
Variable T cannot be equal to 0.
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