Solve quad41/6+21/3

$$\quad 4 \frac { 1 } { 6 } + 2 \frac { 1 } { 3 }$$

Evaluate

$$\frac{13}{2}=6.5$$

Solution Steps

Multiply 4 and 6 to get 24.

$$\frac{24+1}{6}+\frac{2\times 3+1}{3}$$

Add 24 and 1 to get 25.

$$\frac{25}{6}+\frac{2\times 3+1}{3}$$

Multiply 2 and 3 to get 6.

$$\frac{25}{6}+\frac{6+1}{3}$$

Add 6 and 1 to get 7.

$$\frac{25}{6}+\frac{7}{3}$$

Least common multiple of 6 and 3 is 6. Convert \frac{25}{6} and \frac{7}{3} to fractions with denominator 6.

$$\frac{25}{6}+\frac{14}{6}$$

Since \frac{25}{6} and \frac{14}{6} have the same denominator, add them by adding their numerators.

$$\frac{25+14}{6}$$

Add 25 and 14 to get 39.

$$\frac{39}{6}$$

Reduce the fraction \frac{39}{6} to lowest terms by extracting and canceling out 3.

$$\frac{13}{2}$$

Factor

$$\frac{13}{2} = 6\frac{1}{2} = 6.5$$