Solve quad3x+1geq6x-4

$$\quad 3 x + 1 \geq 6 x - 4$$

Solve for x

$$x\leq \frac{5}{3}$$

Solution Steps

Subtract 6x from both sides.

$$3x+1-6x\geq -4$$

Combine 3x and -6x to get -3x.

$$-3x+1\geq -4$$

Subtract 1 from both sides.

$$-3x\geq -4-1$$

Subtract 1 from -4 to get -5.

$$-3x\geq -5$$

Divide both sides by -3. Since -3 is negative, the inequality direction is changed.

$$x\leq \frac{-5}{-3}$$

Fraction \frac{-5}{-3} can be simplified to \frac{5}{3} by removing the negative sign from both the numerator and the denominator.

$$x\leq \frac{5}{3}$$