Solve quad(-6)*((-7)+3-(7+6-14))-7*3=

$$\quad ( - 6 ) \cdot ( ( - 7 ) + 3 - ( 7 + 6 - 14 ) ) - 7 \cdot 3 =$$

Evaluate

$$-3$$

Solution Steps

Add -7 and 3 to get -4.

$$-6\left(-4-\left(7+6-14\right)\right)-7\times 3$$

Add 7 and 6 to get 13.

$$-6\left(-4-\left(13-14\right)\right)-7\times 3$$

Subtract 14 from 13 to get -1.

$$-6\left(-4-\left(-1\right)\right)-7\times 3$$

The opposite of -1 is 1.

$$-6\left(-4+1\right)-7\times 3$$

Add -4 and 1 to get -3.

$$-6\left(-3\right)-7\times 3$$

Multiply -6 and -3 to get 18.

$$18-7\times 3$$

Multiply 7 and 3 to get 21.

$$18-21$$

Subtract 21 from 18 to get -3.

$$-3$$

Factor

$$-3$$