Solve quadtext{6.}49-121p^2

$$\quad \text { 6. } 49 - 121 p ^ { 2 }$$

Differentiate w.r.t. p

$$-242p$$

Steps Using Derivative Rule for Sum

Multiply 6 and 49 to get 294.

$$\frac{\mathrm{d}}{\mathrm{d}p}(294-121p^{2})$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$2\left(-121\right)p^{2-1}$$

Multiply 2 times -121.

$$-242p^{2-1}$$

Subtract 1 from 2.

$$-242p^{1}$$

For any term t, t^{1}=t.

$$-242p$$

Evaluate

$$294-121p^{2}$$

Solution Steps

Multiply 6 and 49 to get 294.

$$294-121p^{2}$$