Solve pmn^2-40lambda+35=0

$$\pm n ^ { 2 } - 40 \lambda + 35 = 0$$

Solve for λ

$$\lambda =\frac{±n^{2}+35}{40}$$

Steps for Solving Linear Equation

Subtract ±n^{2} from both sides. Anything subtracted from zero gives its negation.

$$-40\lambda +35=-\left(±n^{2}\right)$$

Subtract 35 from both sides.

$$-40\lambda =-\left(±n^{2}\right)-35$$

Divide both sides by -40.

$$\frac{-40\lambda }{-40}=\frac{-\left(±n^{2}\right)-35}{-40}$$

Dividing by -40 undoes the multiplication by -40.

$$\lambda =\frac{-\left(±n^{2}\right)-35}{-40}$$

Divide -\left(±n^{2}\right)-35 by -40.

$$\lambda =\frac{±n^{2}}{40}+\frac{7}{8}$$