Solve for r
r = \frac{3 \sqrt{\frac{154}{\pi}}}{10} \approx 2.100422582
r = -\frac{3 \sqrt{\frac{154}{\pi}}}{10} \approx -2.100422582
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\frac{\pi r^{2}}{\pi }=\frac{13.86}{\pi }
Divide both sides by \pi .
r^{2}=\frac{13.86}{\pi }
Dividing by \pi undoes the multiplication by \pi .
r^{2}=\frac{693}{50\pi }
Divide 13.86 by \pi .
r=\frac{231}{5\sqrt{154\pi }} r=-\frac{231}{5\sqrt{154\pi }}
Take the square root of both sides of the equation.
\pi r^{2}-13.86=0
Subtract 13.86 from both sides.
r=\frac{0±\sqrt{0^{2}-4\pi \left(-13.86\right)}}{2\pi }
This equation is in standard form: ax^{2}+bx+c=0. Substitute \pi for a, 0 for b, and -13.86 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
r=\frac{0±\sqrt{-4\pi \left(-13.86\right)}}{2\pi }
Square 0.
r=\frac{0±\sqrt{\left(-4\pi \right)\left(-13.86\right)}}{2\pi }
Multiply -4 times \pi .
r=\frac{0±\sqrt{\frac{1386\pi }{25}}}{2\pi }
Multiply -4\pi times -13.86.
r=\frac{0±\frac{3\sqrt{154\pi }}{5}}{2\pi }
Take the square root of \frac{1386\pi }{25}.
r=\frac{231}{5\sqrt{154\pi }}
Now solve the equation r=\frac{0±\frac{3\sqrt{154\pi }}{5}}{2\pi } when ± is plus.
r=-\frac{231}{5\sqrt{154\pi }}
Now solve the equation r=\frac{0±\frac{3\sqrt{154\pi }}{5}}{2\pi } when ± is minus.
r=\frac{231}{5\sqrt{154\pi }} r=-\frac{231}{5\sqrt{154\pi }}
The equation is now solved.
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