Solve for R
R = \frac{3 \sqrt{\frac{314}{\pi}}}{10} \approx 2.999239468
R = -\frac{3 \sqrt{\frac{314}{\pi}}}{10} \approx -2.999239468
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\frac{\pi R^{2}}{\pi }=\frac{28.26}{\pi }
Divide both sides by \pi .
R^{2}=\frac{28.26}{\pi }
Dividing by \pi undoes the multiplication by \pi .
R^{2}=\frac{1413}{50\pi }
Divide 28.26 by \pi .
R=\frac{471}{5\sqrt{314\pi }} R=-\frac{471}{5\sqrt{314\pi }}
Take the square root of both sides of the equation.
\pi R^{2}-28.26=0
Subtract 28.26 from both sides.
R=\frac{0±\sqrt{0^{2}-4\pi \left(-28.26\right)}}{2\pi }
This equation is in standard form: ax^{2}+bx+c=0. Substitute \pi for a, 0 for b, and -28.26 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
R=\frac{0±\sqrt{-4\pi \left(-28.26\right)}}{2\pi }
Square 0.
R=\frac{0±\sqrt{\left(-4\pi \right)\left(-28.26\right)}}{2\pi }
Multiply -4 times \pi .
R=\frac{0±\sqrt{\frac{2826\pi }{25}}}{2\pi }
Multiply -4\pi times -28.26.
R=\frac{0±\frac{3\sqrt{314\pi }}{5}}{2\pi }
Take the square root of \frac{2826\pi }{25}.
R=\frac{471}{5\sqrt{314\pi }}
Now solve the equation R=\frac{0±\frac{3\sqrt{314\pi }}{5}}{2\pi } when ± is plus.
R=-\frac{471}{5\sqrt{314\pi }}
Now solve the equation R=\frac{0±\frac{3\sqrt{314\pi }}{5}}{2\pi } when ± is minus.
R=\frac{471}{5\sqrt{314\pi }} R=-\frac{471}{5\sqrt{314\pi }}
The equation is now solved.
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