Solve pi(2n+6)^2

$$\pi ( 2 n + 6 ) ^ { 2 }$$

Evaluate

$$4\pi \left(n+3\right)^{2}$$

Solution Steps

Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(2n+6\right)^{2}.

$$\pi \left(4n^{2}+24n+36\right)$$

Use the distributive property to multiply \pi by 4n^{2}+24n+36.

$$4\pi n^{2}+24\pi n+36\pi$$

Expand

$$4\pi n^{2}+24\pi n+36\pi$$

Solution Steps

Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(2n+6\right)^{2}.

$$\pi \left(4n^{2}+24n+36\right)$$

Use the distributive property to multiply \pi by 4n^{2}+24n+36.

$$4\pi n^{2}+24\pi n+36\pi$$