Solve pi(gamma-2)^2

$$\pi ( \gamma - 2 ) ^ { 2 }$$

Expand

$$\pi \gamma ^{2}-4\pi \gamma +4\pi$$

Solution Steps

Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(\gamma -2\right)^{2}.

$$\pi \left(\gamma ^{2}-4\gamma +4\right)$$

Use the distributive property to multiply \pi by \gamma ^{2}-4\gamma +4.

$$\pi \gamma ^{2}-4\pi \gamma +4\pi$$

Evaluate

$$\pi \left(\gamma -2\right)^{2}$$

Solution Steps

Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(\gamma -2\right)^{2}.

$$\pi \left(\gamma ^{2}-4\gamma +4\right)$$

Use the distributive property to multiply \pi by \gamma ^{2}-4\gamma +4.

$$\pi \gamma ^{2}-4\pi \gamma +4\pi$$