Solve pi{left(12/2right)}^2x=10x{left(12/2right)}^3pi*4/3

$$\pi { \left( \frac{ 12 }{ 2 } \right) }^{ 2 } x = 10x { \left( \frac{ 12 }{ 2 } \right) }^{ 3 } \pi \times \frac{ 4 }{ 3 }$$

Solve for x

$$x=0$$

Steps for Solving Linear Equation

Cancel out \pi on both sides.

$$\left(\frac{12}{2}\right)^{2}x=10x\times \left(\frac{12}{2}\right)^{3}\times \frac{4}{3}$$

Divide 12 by 2 to get 6.

$$6^{2}x=10x\times \left(\frac{12}{2}\right)^{3}\times \frac{4}{3}$$

Calculate 6 to the power of 2 and get 36.

$$36x=10x\times \left(\frac{12}{2}\right)^{3}\times \frac{4}{3}$$

Divide 12 by 2 to get 6.

$$36x=10x\times 6^{3}\times \frac{4}{3}$$

Calculate 6 to the power of 3 and get 216.

$$36x=10x\times 216\times \frac{4}{3}$$

Multiply 10 and 216 to get 2160.

$$36x=2160x\times \frac{4}{3}$$

Multiply 2160 and \frac{4}{3} to get 2880.

$$36x=2880x$$

Subtract 2880x from both sides.

$$36x-2880x=0$$

Combine 36x and -2880x to get -2844x.

$$-2844x=0$$

Product of two numbers is equal to 0 if at least one of them is 0. Since -2844 is not equal to 0, x must be equal to 0.

$$x=0$$