Solve operatorname{m}frac{3^frac{1{x}}-1}{3^frac{1{x}}+1}=1

$$\operatorname { m } \frac { 3 ^ { \frac { 1 } { x } } - 1 } { 3 ^ { \frac { 1 } { x } } + 1 } = 1$$

Solve for m

$$m=\frac{3^{\frac{1}{x}}+1}{3^{\frac{1}{x}}-1}$$

$$x\neq 0$$

Steps for Solving Linear Equation

The equation is in standard form.

$$\frac{3^{\frac{1}{x}}-1}{3^{\frac{1}{x}}+1}m=1$$

Divide both sides by \left(3^{x^{-1}}-1\right)\left(3^{x^{-1}}+1\right)^{-1}.

$$\frac{\frac{3^{\frac{1}{x}}-1}{3^{\frac{1}{x}}+1}m\left(3^{\frac{1}{x}}+1\right)}{3^{\frac{1}{x}}-1}=\frac{3^{\frac{1}{x}}+1}{3^{\frac{1}{x}}-1}$$

Dividing by \left(3^{x^{-1}}-1\right)\left(3^{x^{-1}}+1\right)^{-1} undoes the multiplication by \left(3^{x^{-1}}-1\right)\left(3^{x^{-1}}+1\right)^{-1}.

$$m=\frac{3^{\frac{1}{x}}+1}{3^{\frac{1}{x}}-1}$$