Solve operatorname{lom}(-1x)=sqrt{3}

$$\operatorname { lom } ( - 1 x ) = \sqrt { 3 }$$

Solve for l

$$l=-\frac{\sqrt{3}}{mox}$$

$$x\neq 0\text{ and }m\neq 0\text{ and }o\neq 0$$

Steps for Solving Linear Equation

The equation is in standard form.

$$\left(-mox\right)l=\sqrt{3}$$

Divide both sides by -omx.

$$\frac{\left(-mox\right)l}{-mox}=\frac{\sqrt{3}}{-mox}$$

Dividing by -omx undoes the multiplication by -omx.

$$l=\frac{\sqrt{3}}{-mox}$$

Divide \sqrt{3} by -omx.

$$l=-\frac{\sqrt{3}}{mox}$$

Solve for m

$$m=-\frac{\sqrt{3}}{lox}$$

$$x\neq 0\text{ and }o\neq 0\text{ and }l\neq 0$$

Steps for Solving Linear Equation

The equation is in standard form.

$$\left(-lox\right)m=\sqrt{3}$$

Divide both sides by -lox.

$$\frac{\left(-lox\right)m}{-lox}=\frac{\sqrt{3}}{-lox}$$

Dividing by -lox undoes the multiplication by -lox.

$$m=\frac{\sqrt{3}}{-lox}$$

Divide \sqrt{3} by -lox.

$$m=-\frac{\sqrt{3}}{lox}$$