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$\operatorname (h) (x) = \fraction{\exponential{x}{2} + \exponential{6}{x} - 27}{\exponential{x}{2} - 8 x + 7} $
Solve for h
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hx\left(x-7\right)\left(x-1\right)=x^{2}+6^{x}-27
Multiply both sides of the equation by \left(x-7\right)\left(x-1\right).
\left(hx^{2}-7hx\right)\left(x-1\right)=x^{2}+6^{x}-27
Use the distributive property to multiply hx by x-7.
hx^{3}-8hx^{2}+7hx=x^{2}+6^{x}-27
Use the distributive property to multiply hx^{2}-7hx by x-1 and combine like terms.
\left(x^{3}-8x^{2}+7x\right)h=x^{2}+6^{x}-27
Combine all terms containing h.
\frac{\left(x^{3}-8x^{2}+7x\right)h}{x^{3}-8x^{2}+7x}=\frac{x^{2}+6^{x}-27}{x^{3}-8x^{2}+7x}
Divide both sides by -8x^{2}+x^{3}+7x.
h=\frac{x^{2}+6^{x}-27}{x^{3}-8x^{2}+7x}
Dividing by -8x^{2}+x^{3}+7x undoes the multiplication by -8x^{2}+x^{3}+7x.
h=\frac{x^{2}+6^{x}-27}{x\left(x-7\right)\left(x-1\right)}
Divide x^{2}+6^{x}-27 by -8x^{2}+x^{3}+7x.