Solve operatorname{dratik}2x^2-14=-3x

$$\operatorname { dratik } 2 x ^ { 2 } - 14 = - 3 x$$

Solve for a

$$\left\{\begin{matrix}a=\frac{i\left(3x-14\right)}{dk_{2}rtx^{2}}\text{, }&x\neq 0\text{ and }k_{2}\neq 0\text{ and }t\neq 0\text{ and }r\neq 0\text{ and }d\neq 0\\a\in \mathrm{C}\text{, }&\left(d=0\text{ or }r=0\text{ or }t=0\text{ or }k_{2}=0\right)\text{ and }x=\frac{14}{3}\end{matrix}\right.$$

Steps for Solving Linear Equation

Add 14 to both sides.

$$dratik_{2}x^{2}=-3x+14$$

The equation is in standard form.

$$idk_{2}rtx^{2}a=14-3x$$

Divide both sides by idrtk_{2}x^{2}.

$$\frac{idk_{2}rtx^{2}a}{idk_{2}rtx^{2}}=\frac{14-3x}{idk_{2}rtx^{2}}$$

Dividing by idrtk_{2}x^{2} undoes the multiplication by idrtk_{2}x^{2}.

$$a=\frac{14-3x}{idk_{2}rtx^{2}}$$

Divide 14-3x by idrtk_{2}x^{2}.

$$a=-\frac{i\left(14-3x\right)}{dk_{2}rtx^{2}}$$

Solve for d

$$\left\{\begin{matrix}d=\frac{i\left(3x-14\right)}{ak_{2}rtx^{2}}\text{, }&x\neq 0\text{ and }k_{2}\neq 0\text{ and }t\neq 0\text{ and }a\neq 0\text{ and }r\neq 0\\d\in \mathrm{C}\text{, }&\left(r=0\text{ or }a=0\text{ or }t=0\text{ or }k_{2}=0\right)\text{ and }x=\frac{14}{3}\end{matrix}\right.$$

Steps for Solving Linear Equation

Add 14 to both sides.

$$dratik_{2}x^{2}=-3x+14$$

The equation is in standard form.

$$iak_{2}rtx^{2}d=14-3x$$

Divide both sides by iratk_{2}x^{2}.

$$\frac{iak_{2}rtx^{2}d}{iak_{2}rtx^{2}}=\frac{14-3x}{iak_{2}rtx^{2}}$$

Dividing by iratk_{2}x^{2} undoes the multiplication by iratk_{2}x^{2}.

$$d=\frac{14-3x}{iak_{2}rtx^{2}}$$

Divide 14-3x by iratk_{2}x^{2}.

$$d=-\frac{i\left(14-3x\right)}{ak_{2}rtx^{2}}$$