Solve operatorname{an}2alpha=4/3

$$\operatorname { an } 2 \alpha = \frac { 4 } { 3 }$$

Solve for a

$$a=\frac{4}{3n_{2}\alpha }$$

$$\alpha \neq 0\text{ and }n_{2}\neq 0$$

Steps for Solving Linear Equation

The equation is in standard form.

$$n_{2}\alpha a=\frac{4}{3}$$

Divide both sides by n_{2}\alpha .

$$\frac{n_{2}\alpha a}{n_{2}\alpha }=\frac{\frac{4}{3}}{n_{2}\alpha }$$

Dividing by n_{2}\alpha undoes the multiplication by n_{2}\alpha .

$$a=\frac{\frac{4}{3}}{n_{2}\alpha }$$

Divide \frac{4}{3} by n_{2}\alpha .

$$a=\frac{4}{3n_{2}\alpha }$$

Solve for n_2

$$n_{2}=\frac{4}{3a\alpha }$$

$$\alpha \neq 0\text{ and }a\neq 0$$

Steps for Solving Linear Equation

The equation is in standard form.

$$a\alpha n_{2}=\frac{4}{3}$$

Divide both sides by a\alpha .

$$\frac{a\alpha n_{2}}{a\alpha }=\frac{\frac{4}{3}}{a\alpha }$$

Dividing by a\alpha undoes the multiplication by a\alpha .

$$n_{2}=\frac{\frac{4}{3}}{a\alpha }$$

Divide \frac{4}{3} by a\alpha .

$$n_{2}=\frac{4}{3a\alpha }$$