Solve operatorname{Vranium}238*V_{1}=sqrt{3*1.381*10^23/238+6*19}=

$$\operatorname { Vranium } 238 \cdot V _ { 1 } = \sqrt { \frac { 3 \times 1.381 \times 10 ^ { 23 } } { 238 + 6 \times 19 } } =$$

Solve for V

$$V=-\frac{i\times 1250000000\sqrt{91146}}{11V_{1}am_{238}nru}$$

$$m_{238}\neq 0\text{ and }u\neq 0\text{ and }n\neq 0\text{ and }a\neq 0\text{ and }r\neq 0\text{ and }V_{1}\neq 0$$

Steps for Solving Linear Equation

Calculate 10 to the power of 23 and get 100000000000000000000000.

$$Vranium_{238}V_{1}=\sqrt{\frac{3\times 1.381\times 100000000000000000000000}{238+6\times 19}}$$

The equation is in standard form.

$$iV_{1}am_{238}nruV=\sqrt{\frac{12946875000000000000000}{11}}$$

Divide both sides by iranum_{238}V_{1}.

$$\frac{iV_{1}am_{238}nruV}{iV_{1}am_{238}nru}=\frac{1250000000\sqrt{91146}}{11iV_{1}am_{238}nru}$$

Dividing by iranum_{238}V_{1} undoes the multiplication by iranum_{238}V_{1}.

$$V=\frac{1250000000\sqrt{91146}}{11iV_{1}am_{238}nru}$$

Divide \frac{1250000000\sqrt{91146}}{11} by iranum_{238}V_{1}.

$$V=-\frac{1250000000\sqrt{91146}i}{11V_{1}am_{238}nru}$$

Solve for V_1

$$V_{1}=-\frac{i\times 1250000000\sqrt{91146}}{11Vam_{238}nru}$$

$$u\neq 0\text{ and }n\neq 0\text{ and }a\neq 0\text{ and }r\neq 0\text{ and }V\neq 0\text{ and }m_{238}\neq 0$$

Steps for Solving Linear Equation

Calculate 10 to the power of 23 and get 100000000000000000000000.

$$Vranium_{238}V_{1}=\sqrt{\frac{3\times 1.381\times 100000000000000000000000}{238+6\times 19}}$$

The equation is in standard form.

$$iVam_{238}nruV_{1}=\sqrt{\frac{12946875000000000000000}{11}}$$

Divide both sides by iVranum_{238}.

$$\frac{iVam_{238}nruV_{1}}{iVam_{238}nru}=\frac{1250000000\sqrt{91146}}{11iVam_{238}nru}$$

Dividing by iVranum_{238} undoes the multiplication by iVranum_{238}.

$$V_{1}=\frac{1250000000\sqrt{91146}}{11iVam_{238}nru}$$

Divide \frac{1250000000\sqrt{91146}}{11} by iVranum_{238}.

$$V_{1}=-\frac{1250000000\sqrt{91146}i}{11Vam_{238}nru}$$