Solve operatorname{Cf}(-4)=(-4)^2+3(-4)+11/-4+1

$$\operatorname { Cf } ( - 4 ) = \frac { ( - 4 ) ^ { 2 } + 3 ( - 4 ) + 11 } { - 4 + 1 }$$

Solve for C

$$C=\frac{5}{4f}$$

$$f\neq 0$$

Steps for Solving Linear Equation

Calculate -4 to the power of 2 and get 16.

$$Cf\left(-4\right)=\frac{16+3\left(-4\right)+11}{-4+1}$$

Multiply 3 and -4 to get -12.

$$Cf\left(-4\right)=\frac{16-12+11}{-4+1}$$

Subtract 12 from 16 to get 4.

$$Cf\left(-4\right)=\frac{4+11}{-4+1}$$

Add 4 and 11 to get 15.

$$Cf\left(-4\right)=\frac{15}{-4+1}$$

Add -4 and 1 to get -3.

$$Cf\left(-4\right)=\frac{15}{-3}$$

Divide 15 by -3 to get -5.

$$Cf\left(-4\right)=-5$$

The equation is in standard form.

$$\left(-4f\right)C=-5$$

Divide both sides by -4f.

$$\frac{\left(-4f\right)C}{-4f}=-\frac{5}{-4f}$$

Dividing by -4f undoes the multiplication by -4f.

$$C=-\frac{5}{-4f}$$

Divide -5 by -4f.

$$C=\frac{5}{4f}$$

Solve for f

$$f=\frac{5}{4C}$$

$$C\neq 0$$

Steps for Solving Linear Equation

Calculate -4 to the power of 2 and get 16.

$$Cf\left(-4\right)=\frac{16+3\left(-4\right)+11}{-4+1}$$

Multiply 3 and -4 to get -12.

$$Cf\left(-4\right)=\frac{16-12+11}{-4+1}$$

Subtract 12 from 16 to get 4.

$$Cf\left(-4\right)=\frac{4+11}{-4+1}$$

Add 4 and 11 to get 15.

$$Cf\left(-4\right)=\frac{15}{-4+1}$$

Add -4 and 1 to get -3.

$$Cf\left(-4\right)=\frac{15}{-3}$$

Divide 15 by -3 to get -5.

$$Cf\left(-4\right)=-5$$

The equation is in standard form.

$$\left(-4C\right)f=-5$$

Divide both sides by -4C.

$$\frac{\left(-4C\right)f}{-4C}=-\frac{5}{-4C}$$

Dividing by -4C undoes the multiplication by -4C.

$$f=-\frac{5}{-4C}$$

Divide -5 by -4C.

$$f=\frac{5}{4C}$$