Solve for μ
\mu =\frac{1}{1200}\approx 0.000833333
Assign μ
\mu ≔\frac{1}{1200}
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\mu =\frac{15}{18000}
Expand \frac{1.5}{1800} by multiplying both numerator and the denominator by 10.
\mu =\frac{1}{1200}
Reduce the fraction \frac{15}{18000} to lowest terms by extracting and canceling out 15.
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