Solve mu=1/27-1/27+x/27-64/27+frac{80}{27}

$$\mu = \frac { 1 } { 27 } - \frac { 1 } { 27 } + \frac { x } { 27 } - \frac { 64 } { 27 } + \frac { 80 } { 27 }$$

Solve for x

$$x=27\mu -16$$

Steps for Solving Linear Equation

Subtract \frac{1}{27} from \frac{1}{27} to get 0.

$$\mu =\frac{x}{27}-\frac{64}{27}+\frac{80}{27}$$

Add -\frac{64}{27} and \frac{80}{27} to get \frac{16}{27}.

$$\mu =\frac{x}{27}+\frac{16}{27}$$

Since \frac{x}{27} and \frac{16}{27} have the same denominator, add them by adding their numerators.

$$\mu =\frac{x+16}{27}$$

Divide each term of x+16 by 27 to get \frac{1}{27}x+\frac{16}{27}.

$$\mu =\frac{1}{27}x+\frac{16}{27}$$

Swap sides so that all variable terms are on the left hand side.

$$\frac{1}{27}x+\frac{16}{27}=\mu$$

Subtract \frac{16}{27} from both sides.

$$\frac{1}{27}x=\mu -\frac{16}{27}$$

Multiply both sides by 27.

$$\frac{\frac{1}{27}x}{\frac{1}{27}}=\frac{\mu -\frac{16}{27}}{\frac{1}{27}}$$

Dividing by \frac{1}{27} undoes the multiplication by \frac{1}{27}.

$$x=\frac{\mu -\frac{16}{27}}{\frac{1}{27}}$$

Divide \mu -\frac{16}{27} by \frac{1}{27} by multiplying \mu -\frac{16}{27} by the reciprocal of \frac{1}{27}.

$$x=27\mu -16$$

Solve for μ

$$\mu =\frac{x+16}{27}$$

Solution Steps

Subtract \frac{1}{27} from \frac{1}{27} to get 0.

$$\mu =\frac{x}{27}-\frac{64}{27}+\frac{80}{27}$$

Add -\frac{64}{27} and \frac{80}{27} to get \frac{16}{27}.

$$\mu =\frac{x}{27}+\frac{16}{27}$$

Since \frac{x}{27} and \frac{16}{27} have the same denominator, add them by adding their numerators.

$$\mu =\frac{x+16}{27}$$

Divide each term of x+16 by 27 to get \frac{1}{27}x+\frac{16}{27}.

$$\mu =\frac{1}{27}x+\frac{16}{27}$$