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\frac{4}{3}-\log_{8}\left(2\right)
The base 8 logarithm of 16 is \frac{4}{3}.
\frac{4}{3}-\frac{1}{3}
The base 8 logarithm of 2 is \frac{1}{3}.
1
Subtract \frac{1}{3} from \frac{4}{3} to get 1.
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