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\frac{5}{3}-\log_{27}\left(9\right)
The base 8 logarithm of 32 is \frac{5}{3}.
\frac{5}{3}-\frac{2}{3}
The base 27 logarithm of 9 is \frac{2}{3}.
1
Subtract \frac{2}{3} from \frac{5}{3} to get 1.
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