Verify
true
Share
Copied to clipboard
3+\left(\frac{1}{2}\right)^{-1}-\sqrt[3]{125}=0
The base 2 logarithm of 8 is 3.
3+2-\sqrt[3]{125}=0
Calculate \frac{1}{2} to the power of -1 and get 2.
5-\sqrt[3]{125}=0
Add 3 and 2 to get 5.
5-5=0
Calculate \sqrt[3]{125} and get 5.
0=0
Subtract 5 from 5 to get 0.
\text{true}
Compare 0 and 0.
Examples
Quadratic equation
{ x } ^ { 2 } - 4 x - 5 = 0
Trigonometry
4 \sin \theta \cos \theta = 2 \sin \theta
Linear equation
y = 3x + 4
Arithmetic
699 * 533
Matrix
\left[ \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \right] \left[ \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { -1 } & { 1 } & { 5 } \end{array} \right]
Simultaneous equation
\left. \begin{cases} { 8x+2y = 46 } \\ { 7x+3y = 47 } \end{cases} \right.
Differentiation
\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
Integration
\int _ { 0 } ^ { 1 } x e ^ { - x ^ { 2 } } d x
Limits
\lim _{x \rightarrow-3} \frac{x^{2}-9}{x^{2}+2 x-3}