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0-\log_{\frac{1}{2}}\left(8\right)-\log_{12}\left(144\right)
The base 2 logarithm of 1 is 0.
0-\left(-3\right)-\log_{12}\left(144\right)
The base \frac{1}{2} logarithm of 8 is -3.
0+3-\log_{12}\left(144\right)
The opposite of -3 is 3.
3-\log_{12}\left(144\right)
Add 0 and 3 to get 3.
3-2
The base 12 logarithm of 144 is 2.
1
Subtract 2 from 3 to get 1.