\log _ { 0,25 } 8 + \log _ { 4 } 2
Evaluate
-1
Factor
-1
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-\frac{3}{2}+\log_{4}\left(2\right)
The base 0,25 logarithm of 8 is -\frac{3}{2}.
-\frac{3}{2}+\frac{1}{2}
The base 4 logarithm of 2 is \frac{1}{2}.
-1
Add -\frac{3}{2} and \frac{1}{2} to get -1.
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