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\log_{e}\left(1+x\right)-\log_{e}\left(1+x\right)
Apply rule a^{\log_{a}\left(b\right)}=b, where a=e and b=\log_{e}\left(1+x\right).
0
Combine \log_{e}\left(1+x\right) and -\log_{e}\left(1+x\right) to get 0.