Solve lfloor4(5div2)rfloorlfloor(2-3)5rfloor

$$\lfloor 4(5 \div 2) \rfloor \lfloor (2-3)5 \rfloor$$

Evaluate

$$-50$$

Solution Steps

Express 4\times \frac{5}{2} as a single fraction.

$$\lfloor \frac{4\times 5}{2}\rfloor \lfloor \left(2-3\right)\times 5\rfloor$$

Multiply 4 and 5 to get 20.

$$\lfloor \frac{20}{2}\rfloor \lfloor \left(2-3\right)\times 5\rfloor$$

Divide 20 by 2 to get 10.

$$\lfloor 10\rfloor \lfloor \left(2-3\right)\times 5\rfloor$$

The floor of a real number a is the largest integer number less than or equal to a. The floor of 10 is 10.

$$10\lfloor \left(2-3\right)\times 5\rfloor$$

Subtract 3 from 2 to get -1.

$$10\lfloor -5\rfloor$$

The floor of a real number a is the largest integer number less than or equal to a. The floor of -5 is -5.

$$10\left(-5\right)$$

Multiply 10 and -5 to get -50.

$$-50$$

Factor

$$-50$$