Solve lfloor12-(-9+5)rfloor-lfloor(6+8-5rfloor

$$\lfloor 12-(-9+5) \rfloor - \lfloor (6+8-5 \rfloor$$

Evaluate

$$7$$

Solution Steps

Add -9 and 5 to get -4.

$$\lfloor 12-\left(-4\right)\rfloor -\lfloor 6+8-5\rfloor$$

The opposite of -4 is 4.

$$\lfloor 12+4\rfloor -\lfloor 6+8-5\rfloor$$

Add 12 and 4 to get 16.

$$\lfloor 16\rfloor -\lfloor 6+8-5\rfloor$$

The floor of a real number a is the largest integer number less than or equal to a. The floor of 16 is 16.

$$16-\lfloor 6+8-5\rfloor$$

Add 6 and 8 to get 14.

$$16-\lfloor 14-5\rfloor$$

Subtract 5 from 14 to get 9.

$$16-\lfloor 9\rfloor$$

The floor of a real number a is the largest integer number less than or equal to a. The floor of 9 is 9.

$$16-9$$

Subtract 9 from 16 to get 7.

$$7$$

Factor

$$7$$