Solve lfloor-3/5-1rfloor+2

$$\lfloor - \frac{ 3 }{ 5 } -1 \rfloor +2$$

Evaluate

$$0$$

Solution Steps

Convert 1 to fraction \frac{5}{5}.

$$\lfloor -\frac{3}{5}-\frac{5}{5}\rfloor +2$$

Since -\frac{3}{5} and \frac{5}{5} have the same denominator, subtract them by subtracting their numerators.

$$\lfloor \frac{-3-5}{5}\rfloor +2$$

Subtract 5 from -3 to get -8.

$$\lfloor -\frac{8}{5}\rfloor +2$$

Dividing -8 by 5 gives -2 and remainder 2. Rewrite -\frac{8}{5} as -2+\frac{2}{5}.

$$\lfloor -2+\frac{2}{5}\rfloor +2$$

The floor of a real number a is the largest integer number less than or equal to a. The floor of -2+\frac{2}{5} is -2.

$$-2+2$$

Add -2 and 2 to get 0.

$$0$$

Factor

$$0$$