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y-\frac{3}{3^{2}-1}\times 3=2
Consider the first equation. Insert the known values of variables into the equation.
y-\frac{3}{9-1}\times 3=2
Calculate 3 to the power of 2 and get 9.
y-\frac{3}{8}\times 3=2
Subtract 1 from 9 to get 8.
y-\frac{9}{8}=2
Multiply \frac{3}{8} and 3 to get \frac{9}{8}.
y=2+\frac{9}{8}
Add \frac{9}{8} to both sides.
y=\frac{25}{8}
Add 2 and \frac{9}{8} to get \frac{25}{8}.
y=\frac{25}{8} x=3
The system is now solved.