Solve for x
x=y^{2}+3
y\geq 0
Solve for x (complex solution)
x=y^{2}+3
arg(y)<\pi \text{ or }y=0
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\sqrt{x-3}=y
Swap sides so that all variable terms are on the left hand side.
x-3=y^{2}
Square both sides of the equation.
x-3-\left(-3\right)=y^{2}-\left(-3\right)
Add 3 to both sides of the equation.
x=y^{2}-\left(-3\right)
Subtracting -3 from itself leaves 0.
x=y^{2}+3
Subtract -3 from y^{2}.
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