Solve {l}{f(x)=x^4-2x^2+x-1}{x=1}

$$\left. \begin{array}{l}{ f ( x ) = x ^ { 4 } - 2 x ^ { 2 } + x - 1 }\\{ x = 1 }\end{array} \right.$$

Solve for f, x

$$x=1$$

$$f=-1$$

Solution Steps

Consider the first equation. Insert the known values of variables into the equation.

$$f\times 1=1^{4}-2\times 1^{2}+1-1$$

Calculate 1 to the power of 4 and get 1.

$$f\times 1=1-2\times 1^{2}+1-1$$

Calculate 1 to the power of 2 and get 1.

$$f\times 1=1-2+1-1$$

Subtract 2 from 1 to get -1.

$$f\times 1=-1+1-1$$

Add -1 and 1 to get 0.

$$f\times 1=-1$$

Divide both sides by 1.

$$f=-1$$

The system is now solved.

$$f=-1 x=1$$