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Solve for A, B, C
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C=A-7 A+B+C=127 B=3C
Reorder the equations.
A+B+A-7=127 B=3\left(A-7\right)
Substitute A-7 for C in the second and third equation.
B=134-2A A=7+\frac{1}{3}B
Solve these equations for B and A respectively.
A=7+\frac{1}{3}\left(134-2A\right)
Substitute 134-2A for B in the equation A=7+\frac{1}{3}B.
A=31
Solve A=7+\frac{1}{3}\left(134-2A\right) for A.
B=134-2\times 31
Substitute 31 for A in the equation B=134-2A.
B=72
Calculate B from B=134-2\times 31.
C=31-7
Substitute 31 for A in the equation C=A-7.
C=24
Calculate C from C=31-7.
A=31 B=72 C=24
The system is now solved.