Solve for x, y, z
x=1
y=2
z=-3
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y=2x+z+3
Solve 2x-y+z=-3 for y.
x+2x+z+3-z=6 3x-\left(2x+z+3\right)-z=4
Substitute 2x+z+3 for y in the second and third equation.
x=1 z=-\frac{7}{2}+\frac{1}{2}x
Solve these equations for x and z respectively.
z=-\frac{7}{2}+\frac{1}{2}\times 1
Substitute 1 for x in the equation z=-\frac{7}{2}+\frac{1}{2}x.
z=-3
Calculate z from z=-\frac{7}{2}+\frac{1}{2}\times 1.
y=2\times 1-3+3
Substitute 1 for x and -3 for z in the equation y=2x+z+3.
y=2
Calculate y from y=2\times 1-3+3.
x=1 y=2 z=-3
The system is now solved.
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