Solve {l}{1-(15!/13!)(0.7)^13(0.3)^2}{-0.09}

$$\left. \begin{array}{l}{ 1 - ( \frac { 15 ! } { 13 ! } ) ( 0.7 ) ^ { 13 } ( 0.3 ) ^ { 2 } }\\{ - 0.09 }\end{array} \right.$$

Sort

$$-0.09,0.81687977033077$$

Solution Steps

The factorial of 15 is 1307674368000.

$$sort(1-\frac{1307674368000}{13!}\times 0.7^{13}\times 0.3^{2},-0.09)$$

The factorial of 13 is 6227020800.

$$sort(1-\frac{1307674368000}{6227020800}\times 0.7^{13}\times 0.3^{2},-0.09)$$

Divide 1307674368000 by 6227020800 to get 210.

$$sort(1-210\times 0.7^{13}\times 0.3^{2},-0.09)$$

Calculate 0.7 to the power of 13 and get 0.0096889010407.

$$sort(1-210\times 0.0096889010407\times 0.3^{2},-0.09)$$

Multiply 210 and 0.0096889010407 to get 2.034669218547.

$$sort(1-2.034669218547\times 0.3^{2},-0.09)$$

Calculate 0.3 to the power of 2 and get 0.09.

$$sort(1-2.034669218547\times 0.09,-0.09)$$

Multiply 2.034669218547 and 0.09 to get 0.18312022966923.

$$sort(1-0.18312022966923,-0.09)$$

Subtract 0.18312022966923 from 1 to get 0.81687977033077.

$$sort(0.81687977033077,-0.09)$$

To sort the list, start from a single element 0.81687977033077.

$$0.81687977033077$$

Insert -0.09 to the appropriate location in the new list.

$$-0.09,0.81687977033077$$

Evaluate

$$0.81687977033077,\ -0.09$$