Solve {l}{varepsilon-xz/varepsilon=(x)f}{x/-=(x)8}

$$\left. \begin{array}{l}{ \varepsilon - x \frac { z } { \varepsilon } = ( x ) f }\\{ \frac { x } { - } = ( x ) 8 }\end{array} \right.$$

Solve for x

$$x=\frac{\epsilon ^{2}}{z+f\epsilon }$$

$$z\neq -f\epsilon \text{ and }\epsilon \neq 0$$

Steps for Solving Linear Equation

Multiply both sides of the equation by \epsilon .

$$\epsilon \epsilon -xz=xf\epsilon$$

Multiply \epsilon and \epsilon to get \epsilon ^{2}.

$$\epsilon ^{2}-xz=xf\epsilon$$

Subtract xf\epsilon from both sides.

$$\epsilon ^{2}-xz-xf\epsilon =0$$

Subtract \epsilon ^{2} from both sides. Anything subtracted from zero gives its negation.

$$-xz-xf\epsilon =-\epsilon ^{2}$$

Combine all terms containing x.

$$\left(-z-f\epsilon \right)x=-\epsilon ^{2}$$

Divide both sides by -z-f\epsilon .

$$\frac{\left(-z-f\epsilon \right)x}{-z-f\epsilon }=-\frac{\epsilon ^{2}}{-z-f\epsilon }$$

Dividing by -z-f\epsilon undoes the multiplication by -z-f\epsilon .

$$x=-\frac{\epsilon ^{2}}{-z-f\epsilon }$$

Divide -\epsilon ^{2} by -z-f\epsilon .

$$x=\frac{\epsilon ^{2}}{z+f\epsilon }$$