Solve {l}{(a+3)^2+c^2-49/2(a+3)c=1/2}{a^2+c^2-25/2ac=1/2}

$$\left. \begin{array}{l}{ \frac { ( a + 3 ) ^ { 2 } + c ^ { 2 } - 49 } { 2 ( a + 3 ) c } = \frac { 1 } { 2 } }\\{ \frac { a ^ { 2 } + c ^ { 2 } - 25 } { 2 a c } = \frac { 1 } { 2 } }\end{array} \right.$$

Solve for a, c

$$a=5$$

$$c=5$$