Solve {r}{nn-2n}{quad+4}

$$\left. \begin{array} { r } { n n - 2 n } \\ { \quad + 4 } \end{array} \right.$$

Differentiate w.r.t. n

$$2\left(n-1\right)$$

Steps Using Derivative Rule for Sum

Multiply n and n to get n^{2}.

$$\frac{\mathrm{d}}{\mathrm{d}n}(n^{2}-2n+4)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$2n^{2-1}-2n^{1-1}$$

Subtract 1 from 2.

$$2n^{1}-2n^{1-1}$$

Subtract 1 from 1.

$$2n^{1}-2n^{0}$$

For any term t, t^{1}=t.

$$2n-2n^{0}$$

For any term t except 0, t^{0}=1.

$$2n-2$$

Evaluate

$$n^{2}-2n+4$$

Solution Steps

Multiply n and n to get n^{2}.

$$n^{2}-2n+4$$