Solve {r}{71/8}{-55/8}{-quad55/8}

$$\left. \begin{array} { r } { 7 \frac { 1 } { 8 } } \\ { - 5 \frac { 5 } { 8 } } \\ { - \quad 5 \frac { 5 } { 8 } } \end{array} \right.$$

Evaluate

$$-\frac{33}{8}=-4.125$$

Solution Steps

Multiply 7 and 8 to get 56.

$$\frac{56+1}{8}-\frac{5\times 8+5}{8}-\frac{5\times 8+5}{8}$$

Add 56 and 1 to get 57.

$$\frac{57}{8}-\frac{5\times 8+5}{8}-\frac{5\times 8+5}{8}$$

Multiply 5 and 8 to get 40.

$$\frac{57}{8}-\frac{40+5}{8}-\frac{5\times 8+5}{8}$$

Add 40 and 5 to get 45.

$$\frac{57}{8}-\frac{45}{8}-\frac{5\times 8+5}{8}$$

Since \frac{57}{8} and \frac{45}{8} have the same denominator, subtract them by subtracting their numerators.

$$\frac{57-45}{8}-\frac{5\times 8+5}{8}$$

Subtract 45 from 57 to get 12.

$$\frac{12}{8}-\frac{5\times 8+5}{8}$$

Reduce the fraction \frac{12}{8} to lowest terms by extracting and canceling out 4.

$$\frac{3}{2}-\frac{5\times 8+5}{8}$$

Multiply 5 and 8 to get 40.

$$\frac{3}{2}-\frac{40+5}{8}$$

Add 40 and 5 to get 45.

$$\frac{3}{2}-\frac{45}{8}$$

Least common multiple of 2 and 8 is 8. Convert \frac{3}{2} and \frac{45}{8} to fractions with denominator 8.

$$\frac{12}{8}-\frac{45}{8}$$

Since \frac{12}{8} and \frac{45}{8} have the same denominator, subtract them by subtracting their numerators.

$$\frac{12-45}{8}$$

Subtract 45 from 12 to get -33.

$$-\frac{33}{8}$$

Factor

$$-\frac{33}{8} = -4\frac{1}{8} = -4.125$$