Solve {r}{45}{+quad32}{div46}{*quad18}

$$\left. \begin{array} { r } { 45 } \\ { + \quad 32 } \\ { \div 46 } \\ { \times \quad 18 } \end{array} \right.$$

Evaluate

$$\frac{1323}{23}\approx 57.52173913$$

Solution Steps

Reduce the fraction \frac{32}{46} to lowest terms by extracting and canceling out 2.

$$45+\frac{16}{23}\times 18$$

Express \frac{16}{23}\times 18 as a single fraction.

$$45+\frac{16\times 18}{23}$$

Multiply 16 and 18 to get 288.

$$45+\frac{288}{23}$$

Convert 45 to fraction \frac{1035}{23}.

$$\frac{1035}{23}+\frac{288}{23}$$

Since \frac{1035}{23} and \frac{288}{23} have the same denominator, add them by adding their numerators.

$$\frac{1035+288}{23}$$

Add 1035 and 288 to get 1323.

$$\frac{1323}{23}$$

Factor

$$\frac{3 ^ {3} \cdot 7 ^ {2}}{23} = 57\frac{12}{23} = 57.52173913043478$$