Solve {r}{4*(3/2)^3}{-17*3/2}{+9}

$$\left. \begin{array} { r } { 4 \times ( \frac { 3 } { 2 } ) ^ { 3 } } \\ { - 17 \times \frac { 3 } { 2 } } \\ { + 9 } \end{array} \right.$$

Evaluate

$$-3$$

Solution Steps

Calculate \frac{3}{2} to the power of 3 and get \frac{27}{8}.

$$4\times \frac{27}{8}-17\times \frac{3}{2}+9$$

Express 4\times \frac{27}{8} as a single fraction.

$$\frac{4\times 27}{8}-17\times \frac{3}{2}+9$$

Multiply 4 and 27 to get 108.

$$\frac{108}{8}-17\times \frac{3}{2}+9$$

Reduce the fraction \frac{108}{8} to lowest terms by extracting and canceling out 4.

$$\frac{27}{2}-17\times \frac{3}{2}+9$$

Express 17\times \frac{3}{2} as a single fraction.

$$\frac{27}{2}-\frac{17\times 3}{2}+9$$

Multiply 17 and 3 to get 51.

$$\frac{27}{2}-\frac{51}{2}+9$$

Since \frac{27}{2} and \frac{51}{2} have the same denominator, subtract them by subtracting their numerators.

$$\frac{27-51}{2}+9$$

Subtract 51 from 27 to get -24.

$$\frac{-24}{2}+9$$

Divide -24 by 2 to get -12.

$$-12+9$$

Add -12 and 9 to get -3.

$$-3$$

Factor

$$-3$$