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3x+2\times 0.5=\frac{2}{3}
Consider the first equation. Insert the known values of variables into the equation.
3x+1=\frac{2}{3}
Multiply 2 and 0.5 to get 1.
3x=\frac{2}{3}-1
Subtract 1 from both sides.
3x=-\frac{1}{3}
Subtract 1 from \frac{2}{3} to get -\frac{1}{3}.
x=\frac{-\frac{1}{3}}{3}
Divide both sides by 3.
x=\frac{-1}{3\times 3}
Express \frac{-\frac{1}{3}}{3} as a single fraction.
x=\frac{-1}{9}
Multiply 3 and 3 to get 9.
x=-\frac{1}{9}
Fraction \frac{-1}{9} can be rewritten as -\frac{1}{9} by extracting the negative sign.
x=-\frac{1}{9} y=0.5
The system is now solved.