Solve {r}{203/4}{-47/8}

$$\left. \begin{array} { r } { 20 \frac { 3 } { 4 } } \\ { - 4 \frac { 7 } { 8 } } \end{array} \right.$$

Evaluate

$$\frac{127}{8}=15.875$$

Solution Steps

Multiply 20 and 4 to get 80.

$$\frac{80+3}{4}-\frac{4\times 8+7}{8}$$

Add 80 and 3 to get 83.

$$\frac{83}{4}-\frac{4\times 8+7}{8}$$

Multiply 4 and 8 to get 32.

$$\frac{83}{4}-\frac{32+7}{8}$$

Add 32 and 7 to get 39.

$$\frac{83}{4}-\frac{39}{8}$$

Least common multiple of 4 and 8 is 8. Convert \frac{83}{4} and \frac{39}{8} to fractions with denominator 8.

$$\frac{166}{8}-\frac{39}{8}$$

Since \frac{166}{8} and \frac{39}{8} have the same denominator, subtract them by subtracting their numerators.

$$\frac{166-39}{8}$$

Subtract 39 from 166 to get 127.

$$\frac{127}{8}$$

Factor

$$\frac{127}{2 ^ {3}} = 15\frac{7}{8} = 15.875$$