Solve for x, y
x=22
y=16
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y=\frac{48}{3}
Consider the second equation. Divide both sides by 3.
y=16
Divide 48 by 3 to get 16.
2x+16=60
Consider the first equation. Insert the known values of variables into the equation.
2x=60-16
Subtract 16 from both sides.
2x=44
Subtract 16 from 60 to get 44.
x=\frac{44}{2}
Divide both sides by 2.
x=22
Divide 44 by 2 to get 22.
x=22 y=16
The system is now solved.
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